PHP脚本如何执行JS脚本的方法

自主创新 发布于 2014/09/28 14:41
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PHP

模拟登陆、很多操作之类的,算法方法非常,格式化之后仍然看不懂,想直接调用JS可以吗,需要什么插件吗


如js脚本,(网页中调用  javascript:digg.set(563284,'supports')):

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"relative"||f.position==="static"){n+=i.offsetTop;o+=i.offsetLeft}if(f.position==="fixed"){n+=Math.max(h.scrollTop,i.scrollTop);o+=Math.max(h.scrollLeft,i.scrollLeft)}return{top:n,left:o}};c.offset={initialize:function(){if(!this.initialized){var a=document.body,b=document.createElement("div"),d,f,h,i=a.style.marginTop;d={position:"absolute",top:0,left:0,margin:0,border:0,width:"1px",height:"1px",visibility:"hidden"};for(f in d)b.style[f]=d[f];b.innerHTML='<div style="position:absolute;top:0;left:0;margin:0;border:5px solid #000;padding:0;width:1px;height:1px;"><div></div></div><table style="position:absolute;top:0;left:0;margin:0;border:5px solid #000;padding:0;width:1px;height:1px;" cellpadding="0" cellspacing="0"><tr><td></td></tr></table>';
a.insertBefore(b,a.firstChild);d=b.firstChild;f=d.firstChild;h=d.nextSibling.firstChild.firstChild;this.doesNotAddBorder=f.offsetTop!==5;this.doesAddBorderForTableAndCells=h.offsetTop===5;d.style.overflow="hidden";d.style.position="relative";this.subtractsBorderForOverflowNotVisible=f.offsetTop===-5;a.style.marginTop="1px";this.doesNotIncludeMarginInBodyOffset=a.offsetTop===0;a.style.marginTop=i;a.removeChild(b);this.initialized=true}},bodyOffset:function(a){c.offset.initialized||c.offset.initialize();
var b=a.offsetTop,d=a.offsetLeft;if(c.offset.doesNotIncludeMarginInBodyOffset){b+=parseInt(c.curCSS(a,"marginTop",true),10)||0;d+=parseInt(c.curCSS(a,"marginLeft",true),10)||0}return{top:b,left:d}}};c.fn.extend({position:function(){var a;if(this[0]){a=this.offsetParent();var b=this.offset(),d=/^body|html$/i.test(a[0].tagName)?{top:0,left:0}:a.offset();b.top-=G(this,"marginTop");b.left-=G(this,"marginLeft");d.top+=G(a,"borderTopWidth");d.left+=G(a,"borderLeftWidth");a={top:b.top-d.top,left:b.left-
d.left}}return a},offsetParent:function(){for(var a=this[0].offsetParent||document.body;a&&!/^body|html$/i.test(a.tagName)&&c.css(a,"position")=="static";)a=a.offsetParent;return c(a)}});c.each(["Left","Top"],function(a,b){var d="scroll"+b;c.fn[d]=function(f){if(!this[0])return null;return f!==void 0?this.each(function(){this==u||this==document?u.scrollTo(!a?f:c(u).scrollLeft(),a?f:c(u).scrollTop()):this[d]=f}):this[0]==u||this[0]==document?self[a?"pageYOffset":"pageXOffset"]||c.boxModel&&document.documentElement[d]||
document.body[d]:this[0][d]}});c.each(["Height","Width"],function(a,b){var d=b.toLowerCase();c.fn["inner"+b]=function(){return this[0]?c.css(this[0],d,false,"padding"):null};c.fn["outer"+b]=function(h){return this[0]?c.css(this[0],d,false,h?"margin":"border"):null};var f=b.toLowerCase();c.fn[f]=function(h){return this[0]==u?document.compatMode=="CSS1Compat"&&document.documentElement["client"+b]||document.body["client"+b]:this[0]==document?Math.max(document.documentElement["client"+b],document.body["scroll"+
b],document.documentElement["scroll"+b],document.body["offset"+b],document.documentElement["offset"+b]):h===void 0?this.length?c.css(this[0],f):null:this.css(f,typeof h==="string"?h:h+"px")}})})();




以下是问题补充:

@自主创新:补充:格式化之后仍然很难看懂,通过POST,我发现东西不是1点2点的烦,不知道这些程序员是蛇精病还是工具调用生成的 - - (2014/09/28 14:42)
加载中
0
Legend_x
Legend_x

v8,php有v8扩展,但不推荐。

http://cn2.php.net/manual/zh/class.v8js.php

自主创新
自主创新
回复 @自主创新 : 楼下给出答案了。。
自主创新
自主创新
没有案例小菜鸟表示看不太明白
0
自主创新
自主创新
@红薯  @南湖船老大  我一直很关注你们啊
0
自主创新
自主创新






谷歌浏览器抓包出来的get信息

0
自主创新
自主创新

引用来自“Legend_”的评论

v8,php有v8扩展,但不推荐。

http://cn2.php.net/manual/zh/class.v8js.php

能给个案例吗 亲
自主创新
自主创新
回复 @Legend_ : 看懂了感谢 ,不过貌似要装扩展 官方给出的是源代码
Legend_x
Legend_x
http://www.open-open.com/lib/view/open1343470898212.html 看下能明白不
0
南湖船老大
南湖船老大

思路错了,施主还是原路返回重新找条路吧.

学会curl,HTTP协议,利用curl/fsocket/file_get_contents模拟HTTP提交;
反混淆Js代码,理解登陆逻辑中JS的作用(一般是客户端加密密码、二次登陆、密钥获取等)

南湖船老大
南湖船老大
回复 @自主创新 : 嗯 你可以试试
自主创新
自主创新
回复 @南湖船老大 : 哈哈 我JS未入门,有些东西有捷径 自己就不要搞了 ~_~
南湖船老大
南湖船老大
回复 @自主创新 : 没什么算法,就是用了ajax和jsonp而已,流程很复杂,故意防止一般人去模拟的。我当年花了一个通宵才弄清楚,那还是4年前的微博,不过那时候我很菜。现在估计更难了,那你也至少要准备好两个通宵的精力。
自主创新
自主创新
回复 @南湖船老大 : 多谢 找到了,JSV8挺好的,分析算法一次可以,次次这样,总感觉时间是个大问题 ~_~
自主创新
自主创新
回复 @南湖船老大 : 包是能抓,但是分析算法对我来说脑袋不太够用哎。。。
下一页
0
自主创新
自主创新
<?php
$start = microtime(true);
$array = array();
for ($i=0; $i<50000; $i++) $array[] = $i*2;
 
$array2 = array();
for ($i=20000; $i<21000; $i++) $array2[] = $i*2;
 
foreach ($array as $val) {
  foreach ($array2 as $val2) if ($val == $val2) {}
}
echo (microtime(true)-$start)."\n"; // 8.60s
 
 
$start = microtime(true);
$v8 = new V8Js();
$JS = <<< EOT
var array = [];
for (i=0; i<50000; i++) array.push(i*2);
 
var array2 = [];
for (i=20000; i<21000; i++) array2.push(i*2);
 
for (key=0; key<array.length; key++) {
  for (key2=0; key2<array2.length; key2++) if (array[key] == array2[key2]) {}
}
print('done.');
EOT;
$v8->executeString($JS, 'basic.js');

echo ' '.(microtime(true)-$start)."\n"; // 3.49s



网上找到的应该可以用



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