0

char Block[SY][SX]=
{{1,1,1,1,1,1,1,1,1,1,1 },
{1,0,1,0,1,0,0,0,0,0,1 },
{1,0,1,0,0,0,1,0,1,1,1 },
{1,0,0,0,1,0,1,0,0,0,1 },
{1,0,1,1,0,0,1,0,0,1,1 },
{1,0,1,0,1,1,0,1,0,0,1 },
{1,0,0,0,0,0,0,0,1,0,1 },
{1,0,1,0,1,0,1,0,1,0,1 },
{1,0,0,1,0,0,1,0,1,0,1 },
{1,1,1,1,1,1,1,1,1,1,1 }};

char Block[SY][SX]=
{{1,1,1,1,1,1,1,1,1,1,1 },
{1,0,1,0,1,0,0,0,0,0,1 },
{1,0,1,0,0,0,1,0,1,1,1 },
{1,0,0,0,0,0,1,0,0,0,1 },
{1,0,0,1,0,0,1,0,0,1,1 },
{1,0,1,0,0,1,0,1,0,0,1 },
{1,0,0,0,0,0,0,0,1,0,1 },
{1,0,1,0,0,0,1,0,1,0,1 },
{1,0,0,1,0,0,1,0,0,0,1 },
{1,1,1,1,1,1,1,1,1,1,1 }};

```#include <iostream.h>
#include <memory.h>
#include <stdlib.h>

#define SX 11 //宽

#define SY 10 //长

int dx[4]={0,0,-1,1}; //四种移动方向对x和y坐标的影响

int dy[4]={-1,1,0,0};

/*char Block[SY][SX]= //障碍表
{{ 1,1,1,1,1,1,1,1,1,1,1 },
{ 1,0,1,0,1,0,0,0,0,0,1 },
{ 1,0,1,0,0,0,1,0,1,1,1 },
{ 1,0,0,0,0,0,1,0,0,0,1 },
{ 1,0,0,1,0,0,1,0,0,1,1 },
{ 1,0,1,0,0,1,0,1,0,0,1 },
{ 1,0,0,0,0,0,0,0,1,0,1 },
{ 1,0,1,0,0,0,1,0,1,0,1 },
{ 1,0,0,1,0,0,1,0,0,0,1 },
{ 1,1,1,1,1,1,1,1,1,1,1 }};*/

char Block[SY][SX]= //障碍表

{{ 1,1,1,1,1,1,1,1,1,1,1 },
{ 1,0,1,0,1,0,0,0,0,0,1 },
{ 1,0,1,0,0,0,1,0,1,1,1 },
{ 1,0,0,0,1,0,1,0,0,0,1 },
{ 1,0,1,1,0,0,1,0,0,1,1 },
{ 1,0,1,0,1,1,0,1,0,0,1 },
{ 1,0,0,0,0,0,0,0,1,0,1 },
{ 1,0,1,0,1,0,1,0,1,0,1 },
{ 1,0,0,1,0,0,1,0,1,0,1 },
{ 1,1,1,1,1,1,1,1,1,1,1 }};

int MaxAct=4; //移动方向总数

char Table[SY][SX]; //已到过标记

int Level=-1; //第几步

int LevelComplete=0; //这一步的搜索是否完成

int AllComplete=0; //全部搜索是否完成

char Act[1000]; //每一步的移动方向，搜索1000步，够了吧？

int x=1,y=1; //现在的x和y坐标

int TargetX=9,TargetY=8; //目标x和y坐标

int sum1=0,sum2=0;

void Test( );
void Back( );
int ActOK( );
int GetNextAct( );

void main( )
{
memset(Act,0,sizeof(Act)); //清零

memset(Table,0,sizeof(Table));
Table[y][x]=1; //做已到过标记

while (!AllComplete) //是否全部搜索完

{
Level++;LevelComplete=0; //搜索下一步

while (!LevelComplete)
{
Act[Level]=GetNextAct( ); //改变移动方向

if (Act[Level]<=MaxAct)
sum1++;
if (ActOK( )) //移动方向是否合理

{
sum2++;
Test( ); //测试是否已到目标

LevelComplete=1; //该步搜索完成

}
else
{
if (Act[Level]>MaxAct) //已搜索完所有方向

Back( ); //回上一步

if (Level<0) //全部搜索完仍无结果

LevelComplete=AllComplete=1; //退出

}
}
}
}

void Test( )
{
if ((x==TargetX)&&(y==TargetY)) //已到目标

{
for (int i=0;i<=Level;i++)
cout<<(int)Act[i]; //输出结果

cout<<endl;
cout<<Level+1<<" "<<sum1<<" "<<sum2<<endl;
LevelComplete=AllComplete=1; //完成搜索

}
}

int ActOK( )
{
int tx=x+dx[Act[Level]-1]; //将到点的x坐标

int ty=y+dy[Act[Level]-1]; //将到点的y坐标

if (Act[Level]>MaxAct) //方向错误？

return 0;
if ((tx>=SX)||(tx<0)) //x坐标出界？

return 0;
if ((ty>=SY)||(ty<0)) //y坐标出界？

return 0;
if (Table[ty][tx]==1) //已到过？

return 0;
if (Block[ty][tx]==1) //有障碍？

return 0;
x=tx;
y=ty; //移动

Table[y][x]=1; //做已到过标记

return 1;
}

void Back( )
{
x-=dx[Act[Level-1]-1];
y-=dy[Act[Level-1]-1]; //退回原来的点

Table[y][x]=0; //清除已到过标记

Act[Level]=0; //清除方向

Level--; //回上一层

}

int GetNextAct( ) //找到下一个移动方向。这一段程序有些乱，

//仔细看!

{
int dis[4];
int order[4];
int t=32767;
int tt=2;
for (int i=0;i<4;i++)
dis[i]=abs(x+dx[i]-TargetX)+abs(y+dy[i]-TargetY);
for (i=0;i<4;i++)
if (dis[i]<t)
{
order[0]=i+1;
t=dis[i];
}
if (Act[Level]==0)
return order[0];
order[1]=-1;
for (i=0;i<4;i++)
if ((dis[i]==t)&&(i!=(order[0]-1)))
{
order[1]=i+1;
break;
}
if (order[1]!=-1)
{
for (i=0;i<4;i++)
if (dis[i]!=t)
{
order[tt]=i+1;
tt++;
}
}
else
{
for (i=0;i<4;i++)
if (dis[i]!=t)
{
order[tt-1]=i+1;
tt++;
}
}

if (Act[Level]==order[0])
return order[1];
if (Act[Level]==order[1])
return order[2];
if (Act[Level]==order[2])
return order[3];
if (Act[Level]==order[3])
return 5;
}

```

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