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NSString中解析URL
滴滴云服务器,限时包月0.9元,为开发者而生>>>   

总结几种方法达到这种目的。

1.正则表达式法。

NSRegularExpression *expression = [NSRegularExpression regularExpressionWithPattern:@"(?i)//b((?:[a-z][//w-]+:(?:/{1,3}|[a-z0-9%])|www//d{0,3}[.]|[a-z0-9.//-]+[.][a-z]{2,4}/)(?:[^//s()<>]+|//(([^//s()<>]+|(//([^//s()<>]+//)))*//))+(?://(([^//s()<>]+|(//([^//s()<>]+//)))*//)|[^//s`!()//[//]{};:'/".,<>?«»“”‘’]))" options:NSRegularExpressionCaseInsensitive error:NULL];
NSString *someString = @"This is a sample of a http://abc.com/efg.php?EFAei687e3EsA sentence with a URL within it.";
NSString *match = [someString substringWithRange:[expression rangeOfFirstMatchInString:someString options:NSMatchingCompleted range:NSMakeRange(0, [someString length])]];
NSLog(@"%@", match); // Correctly prints 'http://abc.com/efg.php?EFAei687e3EsA'

至于这个正则表达式,是从网上找的,请看这儿

2.系统的NSDataDetector

NSString *string = @"This is a sample of a http://abc.com/efg.php?EFAei687e3EsA sentence with a URL within it.";
NSDataDetector *linkDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:nil];
NSArray *matches = [linkDetector matchesInString:string options:0 range:NSMakeRange(0, [string length])];
for (NSTextCheckingResult *match in matches) {
  if ([match resultType] == NSTextCheckingTypeLink) {
    NSURL *url = [match URL];
    NSLog(@"found URL: %@", url);
  }
}

3.直接操作NSString

NSURL *url;
    NSMutableArray *listItems = [[someString componentsSeparatedByString:@" "] mutableCopy];
for(int i=0;i<[listItems count];i++)
{
    NSString *str=[listItems objectAtIndex:i];
      if ([str rangeOfString:@"http://"].location == NSNotFound)
          NSLog(@"Not url");
      else 
        url=[NSURL URLWithString:str];  
}

 


原文链接:http://blog.csdn.net/favormm/article/details/6213671
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长平狐
发帖于5年前 0回/361阅
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