文件 ip.txt
192.168.0.1 zhangxc
192.168.0.1 zhangxc1
192.168.0.1 zhangxc3
192.168.0.2 zhangc
192.168.0.2 zhangc1
192.168.0.3 zhangc
192.168.0.3 zhangc
192.168.0.3 zhangxc
192.168.0.3 zhangxc
192.168.0.0 zhang
192.168.0.5 zhang
192.168.0.0 zhang
192.168.0.0 zhang
192.168.0.0 zhang2
要求输出如下
192.168.0.1 3
192.168.0.2 2
192.168.0.3 2
192.168.0.5 1
192.168.0.0 2
即ip所对应的用户数
求指导shell如何编写
sort -u ip.txt | awk '{a[$1]++} END{for(i in a)print i,a[i]}'awk '{ips[$1]++} END{for(ip in ips) print ip,ips[ip]}' ip.txt 192.168.0.5 1 192.168.0.0 4 192.168.0.1 3 192.168.0.2 2 192.168.0.3 4cat ip.txt |awk '{print $1}'|sort|uniq -c|sort -rn |awk '{print $2"\t"$1}'192.168.0.3 4
192.168.0.0 4
192.168.0.1 3
192.168.0.2 2
192.168.0.5 1
192.168.0.5 1
192.168.0.0 2
192.168.0.1 3
192.168.0.2 2
192.168.0.3 2
这个是正确的答案！谢谢Redraiment
引用来自“zhailibao”的评论
awk '{ips[$1]++} END{for(ip in ips) print ip,ips[ip]}' ip.txt 192.168.0.5 1 192.168.0.0 4 192.168.0.1 3 192.168.0.2 2 192.168.0.3 4[root @localhost zhangxc]# cat ip.txt | sort -u |awk '{print $1}' |uniq -c
2 192.168.0.0
3 192.168.0.1
2 192.168.0.2
2 192.168.0.3
1 192.168.0.5
这个是你要表达的意思吗？