SpringSide
Hibernate
Spring Data
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applicationContext.xml配置：
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource"/> <property name="jpaVendorAdapter" ref="hibernateJpaVendorAdapter"/> <property name="packagesToScan" value="org.yye.testJpa"/> <property name="jpaProperties"> <props> <!-- 命名规则 My_NAME->MyName --> <prop key="hibernate.ejb.naming_strategy">org.hibernate.cfg.ImprovedNamingStrategy</prop> </props> </property> </bean>实际使用时还是报 Unknown column，生成的sql中并没有按驼峰法反向转换过来：
select user0_.userId as userId1_0_, user0_.created as created2_0_, user0_.email as email3_0_, user0_.loginName as loginNam4_0_, user0_.loginPwd as loginPwd5_0_, user0_.name as name6_0_, user0_.phone as phone7_0_, user0_.roleId as roleId8_0_, user0_.sex as sex9_0_, user0_.status as status10_0_ from tb_user user0_ where user0_.loginName=?
<bean name="emf" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource"/> <property name="packagesToScan"> <list> <value>org.xxx.model</value> </list> </property> <property name="jpaDialect" ref="jpaDialect"/> <property name="jpaVendorAdapter" ref="jpaVendorAdapter"/> <property name="jpaProperties"> <map> <entry key="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect"/> <entry key="hibernate.show_sql" value="true"/> <entry key="hibernate.format_sql" value="false"/> <entry key="hibernate.hbm2ddl.auto" value="update"/> <entry key="hibernate.ejb.naming_strategy" value="org.hibernate.cfg.ImprovedNamingStrategy"/> </map> </property> </bean>生成的SQL:
Hibernate: select employee0_.id as id1_1_0_, employee0_.employee_address as employee2_1_0_, employee0_.employee_age as employee3_1_0_, employee0_.employee_birthday as employee4_1_0_, employee0_.employee_name as employee5_1_0_ from employee employee0_ where employee0_.id=?
我也遇到同样问题，用的是hibernate5作为jpa的实现，要怎么解决。我不想用hibernate4。